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A set of 12 points is given in a plane, of which 5 points are collinear. If no other three points are collinear, find the total number of triangles that can be formed using these points as vertices.

(A) 220

(B) 210

(C) 200

(D) 185

Correct Answer: (B)

1. Total Triangles without Constraints: The total number of ways to select 3 points from 12 points is given by $\binom{12}{3}$.

2. Calculation of Total Selection: $\binom{12}{3} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 2 \times 11 \times 10 = 220$.

3. Subtracting Invalid Combinations: Triangles cannot be formed if the 3 selected points are collinear. There are 5 points that are collinear, so we must subtract the number of ways to pick 3 points from those 5.

4. Calculation of Collinear Selection: $\binom{5}{3} = \frac{5 \times 4}{2 \times 1} = 10$.

5. Final Count: Total valid triangles = $220 - 10 = 210$.

Test Prep Tip: In geometry-based combinatorics, always use the subtraction method: Total possible combinations minus the cases that violate the geometric property (in this case, collinearity). This is generally faster and less error-prone than summing up the individual valid cases.